Calculating resistor value? Cointaker led's

[Luckydogg420]

For my MiniPinball cabinet I want to put 5 cointaker superbright LEDs in the backbox and run them off of 3 AA batteries. Like this

What's the right way of doing this? I'm not an electrical expert, but I can solder a thing or two. Would I be good with a 220ohm resister, or do I even need one since the 3 batteries are 4.5V together.

Or should I get a 4 battery pack and put in a bigger resistor?

 

[sylvain]

If you will be using Cointaker LEDs for pinball 6.3V bulbs applications, then it is simple and you do not need to
worry about a series dropping resistor, as each LED assembly already has its own internal series resistor built-in.

Simply provide a 4 x 1.5V battery holder for a total of 6V supply, and wire it, perhaps with a series on/off switch,
directly to all Cointaker LEDs connected in parallel.
(Those Cointaker LEDs *might* still work, albeit a lot more dim, with a 3 x 1.5V battery holder pack, I do not know).

- Sylvain.

 

[Luckydogg420]

Thanks. They do work with 3 x 1.5V battery holder, and they do seem dim. I thought they were 5V, not 6.3V, so that explanes it.

I do have them in parallel, and plan to put in a switch.

Thanks. I might be able to get this working today.